wxgetShareInfo总是失败，返回错误42

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补充:wxgetShareInfo总是失败，返回错误42，appjsApp({globalData:{shareTicket:,openGid:},onLaunch:fun
展开:问题模块框架类型问题类型API组件名称终端类型微信版本基础库版本API和组件小程序BugwxgetShareInfo工具653240appjsApp({globalData:{shareTicket:,openGid:},onLaunch:function(options){},onShow:function(options){letthat=thisif(options&&optionsscene==1044){thatglobalDatashareTicket=optionsshareTicket}consolelog(onShowoptions=+JSONstringify(options))},getShareTiket:function(cb){letthat=this展示本地存储能力if(thatglobalDatashareTicket){wxgetShareInfo({shareTicket:thatglobalDatashareTicket,success:function(res){consolelog(getShareTiketshareTicket+JSONstringify(res))letjs_encryptedData=resencryptedDataletjs_iv=resivwxlogin({success:function(res){letjs_code=rescodeconsolelog(code+js_code)wxrequest({url:xxxxxxxx,method:POST,data:{code:js_code,appId:xxxxx,encryptedData:js_encryptedData,iv:js_iv},success:function(res){thatglobalDataopenGid=resdataopenGIdconsolelog(getShareTiketopenGid+thatglobalDataopenGid)typeofcb==function&&cb(thatglobalData)},fail:function(err){consolelog(getShareTiketerr+JSONstringify(err))}})}})},fail:function(res){consolelog(res)},complete:function(res){consolelog(res)}})}else{consolelog(不存在shareTicket)}}})代码片段https:developersweixinqqcomsJ0kBS5mR7g4J即速小程序：使用你的代码片段，是可以获取的啊：为什么我这里一直是fail呢，跟网络环境有关系：大哥能不能加个微信请教一下
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